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x^2+0.17x-0.068=0
a = 1; b = 0.17; c = -0.068;
Δ = b2-4ac
Δ = 0.172-4·1·(-0.068)
Δ = 0.3009
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.17)-\sqrt{0.3009}}{2*1}=\frac{-0.17-\sqrt{0.3009}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.17)+\sqrt{0.3009}}{2*1}=\frac{-0.17+\sqrt{0.3009}}{2} $
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